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Does peltier effect account for lose of voltage of the cell?

  1. Oct 24, 2007 #1
    The Peltier effect is the reverse of the Seebeck effect; a creation of a heat difference (between two joint) from an electric voltage.

    This temperature difference gives rise to a seebeck voltage which is opposite to the voltage of the cell. So we can resonably conclude that it can contribute to the loss of voltage of the battery, can't we?

    I understand seebeck effect but not peltier .... I dont understand why heat energy should be released when electron flow from a higher density to lower density site when it is propelled by an energy source (battery).
     
  2. jcsd
  3. Oct 24, 2007 #2
    Well yea...but...


    Why would that ever happen in real life? Once you connect a battery, you get the peltier effect. Adding heat at this point won't change anything. You are trying to out think the process and you really shouldn't.
     
  4. Oct 24, 2007 #3
    Would you explain things, a bit?
     
  5. Oct 25, 2007 #4
    When you apply a voltage, you have the peltier effect. The battery discharges at a rate dependant upon the resistance if the junction times the current flow. While the current flow does carry heat to one side of the junction. There is no Seebeck effect until the battery voltage drops below what the heated junction produces. After the heated junction output voltage is greater than the battery voltage, the Seebeck effect could recharge the battery to the point where the battery voltage equaled heated junction output voltage, but really the voltage would be very small by then.

    The Seebeck voltage really can't contribute to the loss of battery voltage since it does not occur when the battery is connected and charged.
     
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