Does size or mass of a shoe affect its coefficient of friction?

AI Thread Summary
The discussion centers on whether the size or mass of a shoe influences its coefficient of friction. It is noted that mass affects the normal force, which is part of the friction equation, while size does not directly impact the coefficient of friction. However, there is a consideration that larger shoes may have greater mass, potentially affecting friction indirectly. The conversation highlights that the coefficient of friction remains constant for materials regardless of their mass, as long as other factors are equal. Ultimately, the consensus suggests that size does not affect the coefficient of friction directly.
sbayla31
Messages
9
Reaction score
0

Homework Statement



For a shoe, does its size or mass affect its coefficient of friction? Explain their effects.

Homework Equations



Ff=muFn

The Attempt at a Solution



I'm thinking the mass does (because you need the mass to find the normal force) and the size doesn't because it isn't involved in the calculation... but doesn't the mass increase when the size of the shoe increases? :confused:
 
Physics news on Phys.org
I think you are misinterpreting the question a bit. Why would the mass or size of an object affect its coefficient of friction? All else equal, does a 1-kilogram block of steel have a different coefficient of friction than a 1-gram block of steel?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top