Does Summation Over n from -∞ to +∞ in Quantum Mechanics Equal Ψ(x)?

AI Thread Summary
The discussion centers on the summation notation in quantum mechanics, specifically whether the expression ∑cnexp(iknx) = Ψ(x) implies that n ranges from -∞ to +∞. It is argued that this range is necessary for consistency with Fourier series involving complex exponentials. The alternative, using n = 1 to +∞, is noted for cases where the expression relates to sine or cosine functions. Clarity on the range of n is emphasized as essential for proper interpretation. The importance of context in defining the summation index is highlighted.
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Homework Statement
Clarification of Summation index
Relevant Equations
see below
I have a (trivial) question regarding summation notation in Quantum mechanics. Does

∑cnexp(iknx) = Ψ(x) imply that n ranges from -∞ to +∞ (i.e. all possible combinations of n)? i.e.
n

∑exp(iknx)
-∞

I believe it does to be consistent with the Fourier series in terms of complex exponentials.
n = 1 to +∞ would then be used when exp(ikNx) -> sinx/cosx.

Just want to be absolutely sure. Thanks.
 
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knowwhatyoudontknow said:
Homework Statement:: Clarification of Summation index
Relevant Equations:: see below

I have a (trivial) question regarding summation notation in Quantum mechanics. Does

∑cnexp(iknx) = Ψ(x) imply that n ranges from -∞ to +∞ (i.e. all possible combinations of n)? i.e.
n

∑exp(iknx)
-∞

I believe it does to be consistent with the Fourier series in terms of complex exponentials.
n = 1 to +∞ would then be used when exp(ikNx) -> sinx/cosx.

Just want to be absolutely sure. Thanks.
The range of ##n## should be stated or clear from the context.
 
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