Does the Bottom Hinge's Vertical Force on a Door Produce Torque?

  • Thread starter Thread starter hks118
  • Start date Start date
  • Tags Tags
    Statics
AI Thread Summary
The discussion centers on whether the vertical force from the bottom hinge of a door creates torque when the top hinge is considered the pivot point. It is clarified that since the vertical force line passes through the pivot, the lever arm is effectively zero, resulting in no torque being produced. Participants agree that the absence of displacement in the x-direction from the pivot confirms this conclusion. The understanding of torque as force multiplied by lever arm is emphasized. The conversation concludes with the participant feeling confident in completing their homework problem.
hks118
Messages
19
Reaction score
0

Homework Statement


This is a part of a larger problem, but I'm unsure of one part.
Picture a door with its center of mass in its geometric center. The door is hanging on two hinges, one at the top and one at the bottom. If the pivot point while measuring torques is considered to be the top hinge, does the vertical component of the force that the bottom hinge exerts on the door produce and torque?

Homework Equations


Torque=force*lever arm

The Attempt at a Solution


I don't think it does because there is no displacement in the x direction from the pivot, but I'm not sure
 
Physics news on Phys.org
Hi hks118! :smile:
hks118 said:
If the pivot point while measuring torques is considered to be the top hinge, does the vertical component of the force that the bottom hinge exerts on the door produce and torque?

I don't think it does because there is no displacement in the x direction from the pivot

That's correct … the "lever arm" is the distance of the pivot point from the line of force.

Here, the line of the force (the vertical component of the lower hinge reaction) goes through the pivot, so the distance is zero. :wink:
 
tiny-tim said:
Hi hks118! :smile:


That's correct … the "lever arm" is the distance of the pivot point from the line of force.

Here, the line of the force (the vertical component of the lower hinge reaction) goes through the pivot, so the distance is zero. :wink:

Thanks! I can finish the problem in good conscience now
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
4
Views
3K
Replies
2
Views
2K
Replies
5
Views
3K
Replies
30
Views
8K
Replies
14
Views
3K
Replies
14
Views
4K
Back
Top