Does the Limit of a Sum Equal the Sum of the Limits for Vector-Valued Functions?

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Homework Statement



Let r (t)=f(t),g(t),h(t)and s(t)=〈F(t),G(t),H(t)〉.
Show that lim(t→a)(r (t)+s (t))=lim(t→a)[r (t)]+lim(t→a)[s (t)].


Homework Equations





The Attempt at a Solution



I know that if a function r = <f,g,h> and lim(t→a)[r(t)] then lim(t→a)[r(t)] = < lim(t→a)[f(t)], lim(t→a)[g(t)], lim(t→a)[h(t)] >
 
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voodoochild said:

Homework Statement



Let r (t)=f(t),g(t),h(t)and s(t)=〈F(t),G(t),H(t)〉.
Show that lim(t→a)(r (t)+s (t))=lim(t→a)[r (t)]+lim(t→a)[s (t)].


Homework Equations





The Attempt at a Solution



I know that if a function r = <f,g,h> and lim(t→a)[r(t)] then lim(t→a)[r(t)] = < lim(t→a)[f(t)], lim(t→a)[g(t)], lim(t→a)[h(t)] >


OK, so what happens if you apply that last statement to ##\lim_{t\to a}(r(t)+s(t))##?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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