Does this make any sense at all? Surface Area/Integral

[flyingpig]

Homework Statement

Let's say I have a parametric surface \mathbf{r}(u,v) = <x(u,v),y(u,v),z(u,v)>

Let's say I have to solve some surface integral

\iint f(x,y,z)\;dS

Can I do this differential?

dS = |\mathbf{r_u} \times \mathbf{r_v}|dA

also, has anyone noticed how small LaTeX has gotten on PF?

 

[Dick]

Homework Statement

Let's say I have a parametric surface \mathbf{r}(u,v) = <x(u,v),y(u,v),z(u,v)>

Let's say I have to solve some surface integral

\iint f(x,y,z)\;dS

Can I do this differential?

dS = |\mathbf{r_u} \times \mathbf{r_v}|dA

also, has anyone noticed how small LaTeX has gotten on PF?

What do you mean 'can I do it'? If the r_u and r_v are partial derivatives and dA means du*dv, then that's an expression for dS alright.

 

[magicarpet512]

Let's say I have a parametric surface \mathbf{r}(u,v) = <x(u,v),y(u,v),z(u,v)>

Let's say I have to solve some surface integral

\iint f(x,y,z)\;dS

Can I do this differential?

dS = |\mathbf{r_u} \times \mathbf{r_v}|dA

absolutely