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Does this (textbook) circuit diagram contain a mistake?

  1. Feb 26, 2016 #1
    1. The problem statement, all variables and given/known data

    This circuit solves some differential equation, the question is asking for the equation based on the circuit diagram

    b1npQSK.png

    imgur link: http://i.imgur.com/b1npQSK.png


    2. Relevant equations


    3. The attempt at a solution

    I refer to the input terminal for -f(t)...the signal from it doesn't seem to pass through any resistor on its way into the inverting summer, so I've no way (I think) of finding how the signal from -f(t) is scaled in the summer.

    Is this a mistake on the diagram? If not, what am I missing?
     
  2. jcsd
  3. Feb 26, 2016 #2
    Could be a current input rather than a voltage input... or a mistake.
     
  4. Feb 26, 2016 #3

    LvW

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    Yes - I am sure, it is a mistake. The right most amplifier must add up three signals (voltages) - and for this purpose another series resistor is necessary.
     
  5. Feb 26, 2016 #4
    Where does the problem statement say that? Did you leave something out?
     
  6. Feb 27, 2016 #5

    LvW

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    It is the purpose of the circuit to "solve differential equations".
    Hence, it needs an input. Such an input (time domain) is shown as "-f(t) directly at the inv. terminal of an opamp, which - at the same time - receives the sum of two other voltages. However, this addition works only if f(t) also is connected through another resistor (remember the virtual ground principle).
    Thus, without such a resistor the whole circuit makes no sense.
     
  7. Feb 27, 2016 #6
  8. Feb 28, 2016 #7

    LvW

    User Avatar

    A "current input" is nothing else than a voltage input with a corresponding large source resistance (see my answer).
    On the other hand - do you really assume that such a circuit (analog computer circuitry for solving differential equations) is intended to work with current in and voltage out? This would make no sense at all.
     
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