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s = 150m

a = ?

t = ?

vi = 0

vf = 27

Here is what I did:

[tex]27 = at[/tex]

[tex]27/t = a[/tex]

Put a into another unsolved equation.

[tex]150 = 1/2(27/t)t^2[/tex]

[tex]11.1 = t[/tex]

Put the known variable into the first equation.

[tex]27 = a(11.1)[/tex]

[tex]2.43 = a[/tex]

All I did was take variables, and insert it into it's derivative, or antiderivative. I'm getting different answers using other methods. Can someone explain if this is incorrect?

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# Does this work?

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