Here is the info. s = 150m a = ? t = ? vi = 0 vf = 27 Here is what I did: [tex]27 = at[/tex] [tex]27/t = a[/tex] Put a into another unsolved equation. [tex]150 = 1/2(27/t)t^2[/tex] [tex]11.1 = t[/tex] Put the known variable into the first equation. [tex]27 = a(11.1)[/tex] [tex]2.43 = a[/tex] All I did was take variables, and insert it into it's derivative, or antiderivative. I'm getting different answers using other methods. Can someone explain if this is incorrect?