Does two dimensional motion imply conservation of angular momentum?

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In a system with a particle attached to four springs on the xy plane, angular momentum is not conserved if the springs are fixed to external points. Conservation of angular momentum requires no external torque, which is not the case here due to the fixed springs. While the angular momentum vector is orthogonal to the plane of motion, the presence of external forces from the springs introduces torque. If the springs were connected to movable objects, the system could be considered closed, allowing for conservation of angular momentum. Therefore, in this scenario, angular momentum is not constant.
anamariann123
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Hello!

I have a system composed by a particle attached to four springs that lie on the xy plane. The motion of the particle occurs on the xy plane. I wanted to know if the angular momentum is conserved. Thanks for your help :)
 
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Momentum is conserved if there is no external torque. If you have multiple springs going to a point, you probably have some torque on that point.
 
Perhaps you are thinking "the angular momentum vector is perpendicular to the plane of motion. Since this is two dimensional, there cannot be such a vector." That is mistaken. The fact that motion is "two dimensional" means that the motion occurs in two dimensions. It does not mean there is NO third dimension.
 
I know the angular momentum is orthogonal to the plane of motion, but I would like to know if it is constant.
 
Not in general, no. If the springs were attached to other objects that are free to move, it would be, because that would be a closed system. But if springs are attached to fixed points, it's the same as supplying external torque, so angular momentum will not be conserved.
 
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