Domain of y=sqrt(cosx): 1st & 4th Quadrant of Unit Circle

AI Thread Summary
The domain of y = sqrt(cos(x)) is defined where cos(x) is non-negative, which occurs in the first and fourth quadrants of the unit circle. Mathematically, this can be expressed as D = {x | x ∈ [2nπ, (2n+1)π] for any integer n}. The discussion highlights that for values of x where cos(x) is negative, the square root becomes imaginary, thus not part of the domain. The user seeks clarification on the mathematical representation of the domain, particularly regarding the intervals for x. Understanding these intervals is crucial for accurately defining the function's domain.
Calixto
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What would the domain of y = sqrt(cosx) be in mathematical terms. I know that it is all the reals that lie in the first and fourth quadrant of the unit circle, but how would you express that in mathematical terms?
 
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Something like
D=\{x|x\in[\frac{(4n-1)\pi}{2},\frac{(4n+1)\pi}{2}]\}
where n is any integer
 
You first need to define the domain of x.
If x is +60 for example then cos(x)>0 but if it is -60, then it is <0. sqrt of that is an imaginary number which is not defined.

So basically for x>0 domain is (0,1)

I would like to know how Calixto got his answer as I may be wrong.
 
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