Don't understand phrasing of Question

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The discussion revolves around the interpretation of a physics question regarding the rotation of a helical spring around a vertical axis. The main confusion lies in whether the spring is laid flat on the ground while being spun or if it remains upright with the top coil being rotated. Clarification is sought on the mechanics of the rotation and the implications of adding mass to the spring's free end. The reference image is intended to illustrate the concept of moment of inertia, but its relevance is questioned. Overall, the inquiry highlights the challenges non-native speakers face in understanding complex physics terminology and concepts.
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Sorry if this is the wrong place to ask

A helical spring is rotated about one of its ends around a vertical axis. Investigate the expansion of the spring with and without an additional mass attached to its free end.

Does that make sense to you?

Not my question - a non-native-speaker friend asked me to explain the meaning of a few physics questions. I don't really understand the italicized part of this one though...
 
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Basically, you lay the helical spring flat on the ground and spin it about one of its ends.
 
So - a cylindrical spring is sitting upright on the ground. You grab the top most edge, then start moving your arm in a circular motion. Is that it? Or, is the cylindrical spring sitting in the same manner, and you just grab the top most coil then start rotating the spring?
 
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Like this:

http://images.absoluteastronomy.com/images/encyclopediaimages/m/mo/moment_of_inertia_rod_end.png

where the rod is the spring
 
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Nor do I understand that png. Perhaps I'm just daft about this.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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