Don't understand this conditional probabillity example

AI Thread Summary
The discussion centers on a misunderstanding of conditional probability, specifically regarding P(B|A') in a given example. The original poster questions why P(B n A') is stated as 0.2 when they believe it should be 0.15, interpreting it as the probability of B occurring while A does not. Another participant, RGV, expresses gratitude for the clarification but does not provide a definitive answer to the original question. The conversation highlights the importance of accurately interpreting probability diagrams and the values associated with them. Understanding these concepts is crucial for correctly calculating conditional probabilities.
thisischris
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At the bottom of the page (example 2) for question c) P(B|A').

They say P(B n A') = 0.2. But surely it is (B while not A) which in my mind should be 0.15.

Can somebody tell why it is 0.2?
 

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thisischris said:
At the bottom of the page (example 2) for question c) P(B|A').

They say P(B n A') = 0.2. But surely it is (B while not A) which in my mind should be 0.15.

Can somebody tell why it is 0.2?

If the diagram is correct, and if my interpretation of the various numbers there is correct, it should be 0.15, as you want.

RGV
 
Thank you!
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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