Don't understand what the book means, a tensor thing....

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Homework Help Overview

The discussion revolves around understanding a concept from the book "Mathematical Methods for Physicists," specifically regarding the relationship between the cosine of angles in coordinate transformations and partial derivatives. The original poster expresses confusion about how the cosine of the angle between new and old coordinates relates to the definition of aij as partial derivatives.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to connect the definition of aij with the geometric interpretation of angles in the context of coordinate transformations. Some participants provide additional information regarding the mathematical formulation involving partial derivatives.

Discussion Status

The discussion is ongoing, with participants exploring the relationship between the mathematical definitions and geometric interpretations. Some clarification has been offered, but there is no explicit consensus on the understanding of the concept yet.

Contextual Notes

The original poster is seeking clarification on a specific statement from the textbook, indicating a potential gap in understanding the underlying principles of tensor mathematics and coordinate transformations.

Oz123
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Homework Statement


Right, so it's not really an assignment or anything, just confused of what a book says. the book is "mathematical methods for physicists." The screenshot is attached.
The thing that I'm confused about is that it says "As before, aij is the cosine of the angle between x′i and xj ." This is from rotating the coordinates, so x' is the new coordinates whilst x is the old one. And then it defined aij as the partial derivatives of the x'i wrt xj...Now I don't know how the cosine of the angle between x'i and xj is equal to the partial derivative. Can anyone explain this to me? Thank you in advanced!
 

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Here's more info about aij being cosine angles:
 

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If [tex]x'_i = \sum_j a_{ij} x_j[/tex] then [tex] \frac{\partial x'_i}{\partial x_k} = \sum_j a_{ij} \frac{\partial x_j}{\partial x_k} = a_{ik}[/tex] since [tex]\frac{\partial x_j}{\partial x_k} = \delta_{jk}[/tex].
 
Thank you very much!
 

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