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Doppler effect: moving medium.

  1. Jul 3, 2012 #1
    Hi all. I am asking for some help with getting a physical intuition for the following situation:

    Consider an observer and source, at rest. The source emits sound waves of a particular frequency, 'f'. Letting the medium (air for example) between the source and the observer move with a particular velocity, why is it that the frequency of the emitted waves, as detected by the observer, remains unchanged?

    It is intuitively clear that the velocity of the emitted wave increases as the medium gains speed, but it is less clear why the frequency detected by the observer remains unchanged.

    We all know from experience that the sounds in the distance, travelling through moving air, don't get modified in frequency. But why must this be so, physically?

    Any insight would be greatly appreciated!
     
  2. jcsd
  3. Jul 3, 2012 #2

    cepheid

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    Say the speed of sound is v, and the flow rate of air is u. The distance between source and observer is d, which is fixed. The source generates a sound with frequency f. The period is T = 1/f.

    The wavefronts leaving the source travel at speed v relative to the air, and the air travels at speed u relative to the source and the observer. So the wavefront travels at speed v + u between the source and observer. That means that wavefront 1, leaving at t = 0, arrives at time t1 = d/(v+u) later.

    If wavefront 2 leaves at time t = T, it arrives a time t2 = T + d/(v+u) later.

    t2 - t1 = T + d/(v+u) - d/(v+u) = T

    So... the spacing at which the observer receives the wavefronts is still T and is unaffected by the travel time, it would seem.
     
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