Mandanesss Messages 37 Reaction score 0 Thread starter Oct 11, 2007 #1 For my assignment I have to come up with a really complex double or triple integral that equals 30. Would you mind giving me some ideas?
For my assignment I have to come up with a really complex double or triple integral that equals 30. Would you mind giving me some ideas?
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Oct 11, 2007 #2 How about picking some region in the plane (a circle perhaps) that has area 30 or a region in 3d (a sphere perhaps) that has volume 30 and set up the corresponding integral?
How about picking some region in the plane (a circle perhaps) that has area 30 or a region in 3d (a sphere perhaps) that has volume 30 and set up the corresponding integral?
Gib Z Homework Helper Messages 3,341 Reaction score 7 Oct 11, 2007 #3 Set up the integrals as a function and solve accordingly, I will start an example for a single integral. Choose a function, set that as the integrand, set one limit of the integral as another variable, and solve the new function to 30. eg I choose an integrand x^2. So I let [tex]f(t)=\int^t_0 x^2 dx[/tex] Apply the fundamental theorem of calculus we get [tex]f(t) = \frac{t^3}{3}[/tex] So now we can let f(t)=30 and solve accordingly. Do the same but for a double or triple integral.
Set up the integrals as a function and solve accordingly, I will start an example for a single integral. Choose a function, set that as the integrand, set one limit of the integral as another variable, and solve the new function to 30. eg I choose an integrand x^2. So I let [tex]f(t)=\int^t_0 x^2 dx[/tex] Apply the fundamental theorem of calculus we get [tex]f(t) = \frac{t^3}{3}[/tex] So now we can let f(t)=30 and solve accordingly. Do the same but for a double or triple integral.
nicksauce Science Advisor Homework Helper Messages 1,270 Reaction score 8 Oct 11, 2007 #4 1) Pick a function 2) Pick a region/volume 3) Integrate 4) Normalize to 30