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Double Replacement

  1. Mar 30, 2006 #1
    I have a lab report to do with some different reactions to balance. I'm having a little trouble with a few so pleasee help!!

    In the following Double Replacement Reaction equation:
    HCl + NaOH ---> NaCl + H2O

    How can I balance this equation? When balancing it, do I need to regard the Hydroxide as different elements or just as one compound. If I thought them as different elements, there would be 1 H on one side of the yield and two H on the other side.
    If that was the case, I would just add another H to the left side of the yield sign but then the Oxygens woul dbe unequal causing a chain reactio of problems!
    Sorry if this is confusing, but please help!!!!
  2. jcsd
  3. Mar 30, 2006 #2
    touma, I think it is already balanced.
  4. Mar 30, 2006 #3
    Oh ok! So the OH acts seperatly! Ok thanks.
  5. Apr 1, 2006 #4


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    Gold Member

    You want to count elements.

    There are 2 hydrogens on the left and 2 on the right.
    There is 1 oxygen on the left and 1 on the right.
    Same for sodium and chloride.

    If you want to see it in terms of cations and anions you can look at it as:

    HCl + NaOH ---> NaCl + HOH
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