Double slit experiment and wavelengths

AI Thread Summary
In the double-slit experiment, the fringe spacing is directly related to the wavelength of light used. Given a wavelength of 558.0 nm with a fringe spacing of 1.84 mm, changing the wavelength to 335.0 nm will alter the spacing. The relationship can be expressed using the formula d = (λ * L) / spacing, where L remains constant. A mistake was noted in setting up the ratio between the two wavelengths and their corresponding distances. Understanding this relationship is key to solving the problem accurately.
brunettegurl
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Homework Statement



A double-slit experiment is performed with light of wavelength 558.0 nm. The bright interference fringes are spaced 1.84 mm apart on the viewing screen. What will the fringe spacing be if the light is changed to a wavelength of 335.0 nm?

Homework Equations



d= \frac{\lambda * L}{spacing}

The Attempt at a Solution


so our assumption is that everything stays constant while only the wavelength changes and the fringe spacing..right?? i am unable to think ahead of this point ..pls. help
 
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nevermind i made a silly error while trying to set up a ration btw the 2 wavelengths and distances
 
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