Double-slit problem with incident and refracted angles

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The discussion revolves around the double-slit problem involving incident and refracted angles, specifically addressing the path difference between two rays as δ=dsinθ1 - dsinθ2. The participant notes the challenge of adapting the typical double-slit scenario, which usually only considers the exit angle. They seek guidance on deriving the path difference formula in this context and inquire about the physical significance of the positive and negative terms in the equation. Understanding the implications of these terms is crucial for grasping the underlying physics of the problem. The conversation highlights the complexities of applying the double-slit theory to scenarios with both incident and refracted angles.
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Homework Statement


For the given configuration, the path difference between the 2 rays is given as δ=dsinθ1 - dsinθ2

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Homework Equations


Small angle approximation?

The Attempt at a Solution


I'm used to seeing a double-slit situation where only the exit angle is specified, and thus path difference is simply δ=dsinθ. Here, though, we have an incident and refracted θ1 and θ2. Any hints at deriving the following will be appreciated:

δ=dsinθ1 - dsinθ2
 
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Here's a question for you, why do you think one term is positive while the other is negative (i.e. what does it mean physically)?
 
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