Doublie slit w/ electron problem

  • Thread starter Thread starter overside
  • Start date Start date
  • Tags Tags
    Electron Slit
overside
Messages
11
Reaction score
0

Homework Statement



In a Young’s double-sit experiment performed with electrons, the two slits are
separated by a distance of 2.0 x 10^-6m. The first-order bright fringes are located
on the observation screen at an angle of 1.6 x 10^-4 degrees. Find the wavelength
and momentum of the electrons.

Homework Equations



lamda = dsinx/n ?



The Attempt at a Solution



So i think electrons display the same properties as light when fired through the doublie slit thingy, thus I just subed 2E-6m for d and 1.6E-4 degree for x and used

lamda = dsinx

Answers not right though...and I really don't know where to continue from here.
 
Physics news on Phys.org
come on someone help me please D:
 
What results did you get?

ehild
 
Last edited:
OK nevermind, what I did was right, the teacher made type and give wrong angle, thank you anywayz
 
Glad it worked out.

FYI, in the future I recommend posting any final result you calculate. Otherwise people have no way of knowing if you did it correctly all the way through to the end.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...

Similar threads

Back
Top