Doubt with Ampere and Biot-Savart

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SUMMARY

The discussion clarifies the distinction between the Ampère-Maxwell Law and the Biot-Savart Law in calculating the magnetic field B. The user initially misapplied the Biot-Savart integral, failing to account for the dependence of the denominator on the integration variable z'. The correct formulation for the Biot-Savart Law is provided, emphasizing the transition from volume to line integrals for actual line currents. The relationship between these laws is also highlighted, showcasing their fundamental similarity in describing magnetic fields.

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atomqwerty
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Hello,

I think I'm terribly wrong by supossing Ampère-Maxwell and Biot-Savart are referred to the same concept of magnetic field B. For example, for calculating B near an infinite line, I used both, as I understood them, obtaining different expressions (see image). What is that that I don't get?

Thanks
 

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You didn't do the Biot-Savart integral right. Let the wire go up the z-axis, and the integral is

[tex]B(\rho) = \int_{-\infty}^\infty \frac{\mu_0}{4\pi} \frac{I e_z \; dz' \times (\rho e_\rho - z' e_z)}{(\rho^2 + {z'}^2)^{3/2}}[/tex]

You treated the denominator like it doesn't depend on [itex]z'[/itex], but it does. I write it [itex]z'[/itex] to emphasize that it is the integration variable (not the position we want to find the magnetic field at). Consult a table of integrals to easily find the antiderivative.

In general, for some current density [itex]j[/itex], the Biot-Savart Law is

[tex]B(r) = \int_{V'} \mu_0 j(r') \; dV' \times \frac{r - r'}{4 \pi |r - r'|^3}[/tex]

Actual line currents (not densities) just reduce this integral from a volume to a line. Compare with the electric field from some charge density:

[tex]E(r) = \int_{V'} \frac{\rho(r')}{\epsilon_0} \; dV' \frac{r - r'}{4 \pi |r - r'|^3}[/tex]

for vectors [itex]r, r'[/itex]. You can see these are both really the "same" law. The function [itex](r-r')/4\pi|r-r'|^3[/itex] has special significance in 3D space. Wiki "Green's functions" if you're interested in learning about it.
 
Thank you very much, that was really helpful, I appreciate it!

Carlos
 

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