Dr Evil( Straight line motion)

AI Thread Summary
The discussion revolves around a physics problem involving a helicopter with Dr. Evil and secret agent Austin Powers. The helicopter accelerates upward at 5.0 m/s² for 10 seconds, reaching a maximum height of 380 meters when Powers jumps out. After leaving the helicopter, Powers deploys a jet pack 7 seconds later, leading to confusion about his height above ground as calculations suggest he rises to 359.655 meters. The key point clarified is that both the helicopter and Powers continue to ascend briefly after the engine is shut off due to their initial upward velocity. The conversation emphasizes understanding motion dynamics and the effects of acceleration and gravity on both characters.
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Homework Statement



A helicopter carrying Dr. Evil takes off with a constant upward acceleration of 5.0m/s^2. Secret agent Austin Powers jumps on just as the helicopter lifts off the ground. After the two men struggle for 10.0s , Powers shuts off the engine and steps out of the helicopter. Assume that the helicopter is in free fall after its engine is shut off and ignore effects of air resistance

A What is the maximum height above the ground reached by the helicopter?

B Powers deploys a jet pack strapped on his back 7.0 seconds after leaving the helicopter, and then he has constant downward acceleration with magnitude 2.0m/s^(2). How far is powers above the ground when the helicopter crashes into the ground?

Homework Equations



y=yo+vo*t + 1/2*a*t^(2)

Vy=Vo +a*t

vy^(2)=vo^(2) + 2a(y-yo)

The Attempt at a Solution



A)
y=yo+vo*t + 1/2*a*t^(2)
y=1/2*5.0m/s^(2)*100s^(2)=250m

vy=vo+a*t
vy=5.0m/s^(2) * 10=50m/s

vy^(2)=vo^(2) + 2a(y-yo)
0=(50m/s)^(2)+2(-9.81m/s^(2))*y

y=127.4209m + 250m =380mFor part B though I was a bit confused with a part.
This is what I have

y=yo+vo*t + 1/2*a*t^(2)

y=250m + 50m/s*7s + 1/2*(-9.81m/s^(2)) * 49s^(2)
y=359.655m

Here is where I am confused
In the problem it says this:
After the two men struggle for 10.0s , Powers shuts off the engine and steps out of the helicopter

at 10 seconds the helicopter is 250m above the ground and at that point powers leaves the helicopter right? How did his height from the ground increase to 359.655m? Did shutting off the engine take some time?
 
Last edited:
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What is the question at all?

When stepping out of the helicopter, the man has the same upward velocity as that of the helicopter. So it will rise for a while.

ehild
 
I forgot to add the questions ha sorry. There up there now.
 
So both the helicopter and Powers will rise for a while after the powers are shut off.

ehild
 
ehild said:
So both the helicopter and Powers will rise for a while after the powers are shut off.

ehild

Got it and thank you.
 
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