Drawing Methyls & Ethyls: 3-Ethylheptane & 2-Methyl-3-Ethylhexane

  • Thread starter Thread starter peanutthrower
  • Start date Start date
AI Thread Summary
To draw the ethyl isomer 3-ethylheptane, begin with a seven-carbon main chain and add an ethyl group to the third carbon. For the combination of methyl and ethyl in 2-methyl-3-ethylhexane, start with a six-carbon chain, placing a methyl group on the second carbon and an ethyl group on the third carbon. The resulting structures will feature straight chains with branches at the specified carbons. Understanding the placement of these groups is crucial for accurate representation. This process illustrates the fundamentals of drawing branched hydrocarbons.
peanutthrower
Messages
10
Reaction score
0
how do i draw an ethyl isomer? the one I am trying to figure out is 3-ethylheptane oh and how would i draw a combination of methyl and ethyl? (2-methyl-3-ethylhexane)
 
Physics news on Phys.org
wait nevermind i understand it now
 


To draw an ethyl isomer, start by drawing the main carbon chain for the molecule. In this case, for 3-ethylheptane, the main chain would be seven carbons long. Next, locate the third carbon in the chain and add an ethyl group (CH3CH2) to it, making sure to place the ethyl group on the correct side of the chain. The final structure should look like a straight chain with a "branch" coming off at the third carbon.

To draw a combination of methyl and ethyl, such as in 2-methyl-3-ethylhexane, start by drawing the main carbon chain, which in this case would be six carbons long. Next, locate the second carbon in the chain and add a methyl group (CH3) to it. Then, locate the third carbon and add an ethyl group (CH3CH2) to it. The final structure should look like a straight chain with a "branch" at the second carbon with a methyl group and a "branch" at the third carbon with an ethyl group.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top