Dropping springs (in free fall) and hoberman ball

AI Thread Summary
When a spring is dropped at equilibrium, it remains stationary until the top part touches the bottom, at which point it falls as a whole. For a Hoberman ball, its behavior depends on its state when released; if expanded, it contracts immediately upon release, falling as a smaller ball, while if contracted, it does not expand during the fall. In a free-fall scenario, the spring behaves similarly to the first case, remaining stationary until the top touches the bottom before falling together. The tension in the spring becomes zero during the drop, affecting its motion. Overall, both the spring and Hoberman ball exhibit unique behaviors based on their initial conditions and the influence of gravity.
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Homework Statement


A) Explain what will happen if I drop a spring at equilibrium.
B) Explain what will happen if I drop a Hoberman ball.
C) Explain what will happen if I drop the spring in a falling elevator (in free fall).


Homework Equations


T=kx


3. The Attempt at a Solution [/b
For A) The bottom of the spring will remain stationary until the top bit has touched it because extension x only changes then and consequently T becomes zero and the whole spring then falls together.
I'm not sure if this applies to the Hoberman ball question though. It may depend on whether the ball is expanded/contracted when I release it. If it's expanded, as I release it the ball no longer feels the tension so it will contract at once and fall as a small ball? If it's contracted in the first place, it won't expand and become larger as it falls, will it?
For C) will the effects be the same as in A??
 
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The spring will remain stationary until the top bit has touched it and then the whole spring will fall together.
 
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