E in the charged parallel-plate air capacitor,,,

[karenara]

Homework Statement

I want to know whether the magnitude of the charged electric field in the parallel plate-air capacitor is always delta/epsilon...
In the last image, I have to put E=delta/2epsilon unlike the two situations above. What's the difference between the last one and the first two?? Why can't I put E=delta/epsilon??[/B]

The question is from 'young and freedman university physics' chapter 24. capacitance and dieleectrics question number 76.

The Attempt at a Solution

mentioned above.

 

[anathema]

Hello,

Thank you for your question. The magnitude of the charged electric field in a parallel plate-air capacitor is not always equal to delta/epsilon. It depends on the specific situation and the factors that affect the electric field.

In the first two situations, the electric field is uniform and points from one plate to the other. In this case, the magnitude of the electric field can be calculated using the equation E=delta/epsilon.

In the last situation, the electric field is not uniform. It is stronger near the edges of the plates and weaker in the middle. In this case, the magnitude of the electric field cannot be calculated using the simple equation E=delta/epsilon. Instead, you need to use a more complex equation that takes into account the non-uniformity of the electric field. This is why the equation E=delta/2epsilon is used in the last situation.

I hope this helps to clarify the difference between the last situation and the first two. It is important to carefully consider the specific factors and conditions when calculating the magnitude of the electric field in a parallel plate-air capacitor.