Earth's charge and number of its electron per sq. meter

AI Thread Summary
The discussion revolves around calculating the net charge of the Earth and the corresponding number of excess electrons per square meter. The net charge was determined to be approximately -7.56E+05 C, and the participants discussed how to derive the number of excess electrons by dividing the total charge by the charge of a single electron. It was clarified that the calculated number represented total electrons, not just excess ones, and that the problem specifically asks for the excess electrons per square meter. Participants suggested considering the Earth's surface area to find the distribution of excess electrons. The conversation emphasizes the importance of understanding how to apply the charge calculations to the Earth's surface area for accurate results.
Hooke's Law
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Homework Statement


The Earth is surrounded by an electric field, pointing inward at every point. Assume a magnitude of E = 167N/C near the surface. What is the net charge on the Earth?
How many excess electrons per square meter on the Earth's surface does this correspond to?


Homework Equations



E = kq/r^2


The Attempt at a Solution



In the first question I got an answer of -7.56E+05 C, but I don't know how to start with the 2nd one.
 
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If you have the number of coulombs, and each electron has a charge of e- coulombs,...

If I may make a small suggestion, if you do the problem strictly symbolically (don't plug in any numbers until the very end) and you know that k = 1/(4 π εo), then you will amazed at how many things cancel out, and thus how many things you don't need to look up values for.
 
gneill said:
If you have the number of coulombs, and each electron has a charge of e- coulombs,...

If I may make a small suggestion, if you do the problem strictly symbolically (don't plug in any numbers until the very end) and you know that k = 1/(4 π εo), then you will amazed at how many things cancel out, and thus how many things you don't need to look up values for.


I got the net charge of the earth. Should I divide that charge by the charge of one electron ( -1.6022*10^-19) ? I tried it but it didnt work..
 
Hooke's Law said:
I got the net charge of the earth. Should I divide that charge by the charge of one electron ( -1.6022*10^-19) ? I tried it but it didnt work..

In what way did it not work? Did it not give you a figure for the total number of electrons?
 
n = total charge / electron charge = 4.71*10^24

The computer won't accept it, and did I do it right?
 
Hooke's Law said:
n = total charge / electron charge = 4.71*10^24

The computer won't accept it, and did I do it right?

You've done it right so far. You're not quite done yet! What precisely does the problem want you to find?
 
It's asking the number of excess electrons per square meter on the Earth's surface.

So I guess the value that I got in my previous post is the the number of electrons but not the excess ones, am I right? How do I find the excess electrons? Does "electrons per square meter" contribute to the problem?

Thanks
 
Hooke's Law said:
It's asking the number of excess electrons per square meter on the Earth's surface.

So I guess the value that I got in my previous post is the the number of electrons but not the excess ones, am I right? How do I find the excess electrons? Does "electrons per square meter" contribute to the problem?

Thanks

The number you calculated is the number of electrons in excess. You just haven't spread them out evenly over the surface of the Earth yet to find out how many fit per square meter.
 
So is there some integral needed? integral of the volume of the Earth(sphere)? from 0 to 1 where the numbers correspond the number of squares.
 
  • #10
Hooke's Law said:
So is there some integral needed? integral of the volume of the Earth(sphere)? from 0 to 1 where the numbers correspond the number of squares.

The Earth is (to a good approximation) a sphere. What's the surface area of a sphere?
 
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