1. The problem statement, all variables and given/known data A skier of mass 55.0 kg slides down a slope 11.7 m long, inclined at an angle θ to the horizontal. The magnitude of kinetic friction is 41.5 N. The skier's initial speed is 65.7 cm/s (0.657 m/s) and the speed at the bottom of the slope is 7.19 m/s. Determine the angle θ from the law of conservation of energy. Air resistance does not matter. 2. Relevant equations Ek = 1/2*m*v^2 Eg = mgh Ethermal = W = Fk*cosθ*Δd 3. The attempt at a solution Eth= Fk*cosθ*Δd Substituted in the values, then used conserv. of energy: mgh + 1/2*mv^2 = 1/2*mv^2 + Eth where h = 11.7/sinθ. But I got stuck solving for the angle. Where did I go wrong?