Effect of friction on the foward momentum of an object

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Friction affects the forward momentum of a thrown object, such as a ball, by decreasing its speed due to air resistance, which is often modeled by the formula F(friction) = -bv. The trajectory of the ball is a parabolic curve that becomes 'squashed' at the end due to this frictional force. A user clarified that "mall" was a typo and meant "ball," which led to a discussion about the implications of air resistance on the ball's motion. The conversation also touched on the concept of Reynolds Number, questioning whether a ball thrown at 100 mph would have a high value. Understanding these principles is crucial for analyzing the motion of objects in fluid dynamics.
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for example, if a mall is thrown, it forms a parabola, but its speed also decreases due to the friction in air.
what is the formula for that decrease?
what is the shape of the revised curve?
thanks.
 
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As a rule of thumb, friction is usually proportional to speed, often quoted as: F(friction)= -bv,
The revised curve is a parabola with a 'squashed' end half.
 
NoobixCube said:
As a rule of thumb, friction is usually proportional to speed, often quoted as: F(friction)= -bv,
The revised curve is a parabola with a 'squashed' end half.


I'm guessing you don't mean "shopping mall". That would have a lot of wind resistance, and would not travel very far when you threw it.

A google search on air resistance gives many useful hits. Here's the first{

http://en.wikipedia.org/wiki/Drag_(physics )


.
 
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sorry "mall" was a typo, i meant ball.
another question on this topic:
assuming that a ball is thrown at a 100mph (in regular air) does that have a high Reynold's Number or not?
sorry, i do not take physics, so this might be a stupid question.
 

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