Effect of Increasing Wire Width on Resistance

AI Thread Summary
Increasing the width of a wire reduces its electrical resistance due to a larger cross-sectional area, allowing more electrons to flow freely. This relationship is captured by the formula R = ρL/A, where R is resistance, ρ is resistivity, L is length, and A is the cross-sectional area. As the area increases, resistance decreases, similar to how a wider pipe allows more water to flow. The resistivity (ρ) and length (L) of the wire remain constant in this scenario. Understanding this principle is essential for applications in electrical engineering and materials science.
scotty0409
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What is the effect of increasing the width of a wire on it's resistance, and why?

Thanks
Neil
 
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What do you think? Do you know the structure of a metal/solid?
 
Does it decrease because there are more electrons to move freely?
 
scotty0409 said:
Does it decrease because there are more electrons to move freely?

You pretty much got it. Just think of a pipe where you can vary the diameter to affect the water flow.
 
ok thanks for the help
 
So now that you've figured it out with help from ranger, here is the general equation that you should memorize (yes, there are a handful of equations that you should memorize):

R = \frac{\rho L}{A}

So an increase in the "width" of a conductor increases the area of the conductor, which does what?
 
berkeman said:
So now that you've figured it out with help from ranger, here is the general equation that you should memorize (yes, there are a handful of equations that you should memorize):

R = \frac{\rho L}{A}

So an increase in the "width" of a conductor increases the area of the conductor, which does what?

Sorry, but what does pL represent?
 
p = static resistivity of material and L = length of specimen.
 
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