Efficiency of a 265W Motor at 4.30A from 120V Line | Energy Usage in 1.50 Hours

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In summary, the efficiency of a 265W motor that draws 4.30A from a 120V line can be calculated using the equations P=IV and P=V^2/R. To find the energy used in Joules, the equation W=IVt can be used, where W is energy in Joules, I is current in Amps, V is voltage in Volts, and t is time in hours. Efficiency is defined as the output power divided by the input power. By plugging in the given values, the efficiency and energy usage of the motor can be determined.
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aMo0oDi
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What is the efficiency of a 265W motor that draws 4.30A from 120V line?
How much energy in Joules does this motor use in 1.50 hour?

thanks in advance..
 
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  • #2
What have you tried? Do you know what power is?
 
  • #3
power has two equations :
1) P(t)= W/t = -PE/t = q.V/t = I.V
2) P= I (I.R)
 
  • #4
aMo0oDi said:
power has two equations :
1) P(t)= W/t = -PE/t = q.V/t = I.V
2) P= I (I.R)

Power can also be expressed as P=V^2/R

Now what is efficiency defined as?

Finally, what information are you given and what can you do with it?
 
  • #5
aMo0oDi said:
power has two equations :
1) P(t)= W/t = -PE/t = q.V/t = I.V
2) P= I (I.R)
If W/t=IV
W=J/s
I=Amps
V=Volts

You just plug it in, then find the efficiency.
 

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