Effort/ Load simple machines question

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SUMMARY

The discussion centers on calculating the effort required to lift a 900 kg vehicle using a screw jack with a handle length of 24 cm and a pitch of 2 mm, assuming 100% efficiency. The velocity ratio (VR) is established as 2, leading to a mechanical advantage (MA) calculation of 450 kg. The user expresses confusion regarding the application of these concepts in physics, specifically in determining the effort needed for the lift.

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Homework Statement


A screw jack that is used on cars whenever tyres are changed by the owner. The screw moves though a distance equal to its pitch whenever the effort lever ( jack handle) is given a complete turn. If the length of the jack handle is 24cm, the pitch is 2mm and the jack is required to lift a 900kg vheicle. Assuming efficiency is 100%. calculate the Effort reqired to lift the car.

Given Length of 24cm
Pitch of 2mm
Mass of 900kg
100% efficiency

Homework Equations


Velocity ratio
Mechanical advantage

The Attempt at a Solution



VR = 2
MA = L/E

900/2

450kg
 
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helppppp
 
no help for this?

I've also assumed as the handle of 24cm goes around 1 complete turn, the jack goes up 2mm. Also gravity on the 900kg of the Load.

But its so confusing. And I'm new to physics can someone help me..
 

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