Eigenfunctions and hermitian operators

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A wavefunction can be an eigenfunction of two different Hermitian operators, A_1 and A_2, represented by the equations A_1ψ = a_1ψ and A_2ψ = a_2ψ. When applying these operators in succession, the order does not affect the outcome, indicating that the operators commute. This commutation implies that the two operators can be simultaneously diagonalized, allowing for a common set of eigenfunctions. Additionally, when considering two different wavefunctions as eigenfunctions of the same Hermitian operator with distinct eigenvalues, they remain orthogonal. The discussion emphasizes the fundamental properties of Hermitian operators and their eigenfunctions in quantum mechanics.
baldywaldy
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Hi. I'm just a bit stuck on this question:

Write down two equations to represent the fact that a given wavefunction is simultaneously an eiigenfunction of two different hermitian operators. what conclusion can be drawn about these operators?

Im not quite sure how to start it.

Thanks!
 
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baldywaldy said:
Hi. I'm just a bit stuck on this question:

Write down two equations to represent the fact that a given wavefunction is simultaneously an eiigenfunction of two different hermitian operators. what conclusion can be drawn about these operators?

Im not quite sure how to start it.

Thanks!
If \psi is an eigenfunction of the hermitian operator A_1, what does this mean? Can you write the eigenvalue problem?
 
is it.

phi|A>= a|A> ?
 
baldywaldy said:
is it.

phi|A>= a|A> ?
Yes. So, we have (preserving the index):

A_1 \psi = a_1\psi.

Suppose we now have a second hermitian operator, A_2. Can you write a similar equation?
 
Hootenanny said:
Yes. So, we have (preserving the index):

A_1 \psi = a_1\psi.

Suppose we now have a second hermitian operator, A_2. Can you write a similar equation?

A_2 \psi = a_2\psi.
 
baldywaldy said:
A_2 \psi = a_2\psi.
Excellent!

So what happens if you first operate on \psi with A_1, followed by A_2? Compare this with what happens when you do it the other way round.
 
Hootenanny said:
Excellent!

So what happens if you first operate on \psi with A_1, followed by A_2? Compare this with what happens when you do it the other way round.

A_2A_1\psi = A_2(A_1\psi) =A_2(a1\psi)=a_1A_2\psi= a_1a_2\psi

A_1A_2\psi=a_2a_1\psi

Therefore they commute! XD
 
baldywaldy said:
A_2A_1\psi = A_2(A_1\psi) =A_2(a1\psi)=a_1A_2\psi= a_1a_2\psi

A_1A_2\psi=a_2a_1\psi

Therefore they commute! XD
Indeed they do! :approve:
 
Hootenanny said:
Indeed they do! :approve:

Thanks! :Danother similar question to that one I have is :

write down two equations to represent the fact that two different wavefunctions are simultaneously eigenfunctions of the same hermation operator, with different eigenvalues. what conclusion can be drawn about these wavefunctions. So far I have

A_1\psi=a_1\psi

A_1θ=a_1θ
 
  • #10
Shouldn't there be a2 for the second line ?
 
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