Eigenfunctions of an Integral Operator

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Kreizhn
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Homework Statement



If there are any eigenvalues for the following integral operator, calculate them

[tex]Kf(t) = \int_0^1 (1+st) f(s) \ ds[/tex]

The Attempt at a Solution



I've tried making this into a differential equation, to no avail. I've also just tried solving the equation [itex]Kf(t) = \lambda f(t)[/itex] though that also didn't lead anywhere. I'm not sure if there's some special way of attacking problem like this. Does anybody have any ideas?
 
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not too sure.. but how about noticing the t depndence of the function... does the fact
[tex]\int_0^1 f(s) ds[/tex]
and
[tex]\int_0^1 sf(s) ds[/tex]
are constants help..
 
I had tried looking for eigenfunctions of the form [itex]a + bt[/itex] but for some reason got an inconsistent system of equations. I'll go back and look at it again.
 
i haven't tried, but for non-zero b
(a+bt) = b(a/b+t)

so if (a+bt) is an eigenfunction, then so is (a/b+t) = c+t which ma be easier to deal with
 
So if try a function of the form [itex]f(t) = t + a[/itex] and try [itex]K f(t) = \lambda f(t)[/itex] I get the following system of equations
[tex]\begin{align*}<br /> \frac13 + \frac a2 &= \lambda \\<br /> \frac12 + a &= \lambda a<br /> \end{align*}[/tex]

I can solve this to get [itex]a = 1.868517092, \lambda = 1.267591879[/itex]. But it seems odd that an integral operator would only have one eigenvalue in it's spectrum. Furthermore, how can I be sure that this is exhaustive? How would I find other eigenvalues and eigenfunctions?
 
Indeed, so you're saying that the only possible eigenfunctions are of the form [itex]f(t) = t+a[/itex] since for all other functions, [itex]Kf(t)[/itex] will be first order polynomial in t.
 
Kreizhn said:
So if try a function of the form [itex]f(t) = t + a[/itex] and try [itex]K f(t) = \lambda f(t)[/itex] I get the following system of equations
[tex]\begin{align*}<br /> \frac13 + \frac a2 &= \lambda \\<br /> \frac12 + a &= \lambda a<br /> \end{align*}[/tex]

I can solve this to get [itex]a = 1.868517092, \lambda = 1.267591879[/itex]. But it seems odd that an integral operator would only have one eigenvalue in it's spectrum. Furthermore, how can I be sure that this is exhaustive? How would I find other eigenvalues and eigenfunctions?

Don't you get a quadratic equation in lambda? Aren't there two eigenvalues?
 
Yes. I was being lazy an had plugged this into a Maple to solve numerically. But it isn't hard to do algebraically. I realized this, but figured the thread was dead so it wasn't important to post it :P
 
Kreizhn said:
Yes. I was being lazy an had plugged this into a Maple to solve numerically. But it isn't hard to do algebraically. I realized this, but figured the thread was dead so it wasn't important to post it :P

Sure. Just checking...