Eigenfunctions orthogonal in Hilbert space

gfd43tg
Gold Member
Messages
947
Reaction score
48
Hello,

I am having a question regarding how eigenfunctions are orthogonal in Hilbert space, or what does that even mean (other than the inner product is zero). I mean, I know in ##\mathbb {R^{3}}##, vectors are orthogonal when they are right angles to each other.

However, how can functions be "orthogonal", in the sense of being perpendicular, and does Hilbert Space have infinite dimensions?
 
Physics news on Phys.org
Maylis said:
I am having a question regarding how eigenfunctions are orthogonal in Hilbert space, or what does that even mean (other than the inner product is zero).

There is no other meaning to it, it simply means the inner product between the functions is zero. The geometrical interpretation for ##\mathbb R^n## is that two orthogonal vectors are at right angle to each other, but really this is also a matter of definition of orthogonality.

Maylis said:
and does Hilbert Space have infinite dimensions?

It can have infinite dimensions, yes. It can even be non-separable. It does not have to be infinite dimensional.
 
But how can you even take the inner product of functions? I thought this was something you did with vectors. For example, what's the inner product of ##f_{1}(x) = x## and ##f_{2}(x) = x^{2}##? This doesn't mean anything to me
 
Maylis said:
But how can you even take the inner product of functions? I thought this was something you did with vectors. For example, what's the inner product of ##f_{1}(x) = x## and ##f_{2}(x) = x^{2}##? This doesn't mean anything to me
For functions, the inner product is usually defined (in physics) as
$$
\langle f, g \rangle \equiv \int_a^b f^* g \, d\tau
$$
where ##a## and ##b## are appropriate limits and the integration element ##d\tau## will depend on how the function is expressed. In 1D, ##d\tau## will usually be ##dx## or ##dp##.
 
Maylis said:
But how can you even take the inner product of functions? I thought this was something you did with vectors. For example, what's the inner product of ##f_{1}(x) = x## and ##f_{2}(x) = x^{2}##? This doesn't mean anything to me

Function spaces can also be vector spaces. As long as you can add functions and multiply them by constants and still be within the function space (with all of the relevant requirements fulfilled), it is a vector space. For example, the identity vector under addition is simply the zero function, for which f(x) = 0 for all x. The inner product that DrClaude mentions fulfils all of the requirements of an inner product (sometimes it will also come with an additional weight function), which you can check by simply ticking off the axioms for an inner product. A function space which is a vector space endowed with an inner product is an inner product space. A Hilbert space is essentially an inner product space where all Cauchy sequences converge to an element in the space.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
Back
Top