Eigenvalues and eigenvectors of a linear transform

smithg86
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Homework Statement



Find all the eigenvalues and eigenvectors of the linear transformation:
T(f) = 5f ' -3f
T: from C^(nfnty) --> C^(nfnty)
where C^(nfnty) is set of continuously functions

Homework Equations



A scalar B is called an eigenvalue of T if there exists a nonzero element f of C such that:
T(f) = Bf

The Attempt at a Solution



didn't know where to start
 
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You do know where to start. You have said you need to find all functions f and a scalars, B so that

5f'-3f=Bfso find them. That part is first year calculus: first order linear homogeneous differential equation.
 
T(f)=Bf so 5*f'-3*f=B*f. It's an ODE. Solve it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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