I'm having some trouble with some homework and I'm hoping someone can help me.(adsbygoogle = window.adsbygoogle || []).push({});

PROBLEM:

#6. Cart1, with mass m, is initially at rest and is struck by cart2,

which has a mass of 336 kg and initial speed of 1.81 m/s. The collision

is elastic and after the collision cart2 continues to move in its

original direction at 0.807 m/s. Find m, the mass of cart1.

#7.Find the speed of cart1 after the collision.

ATTEMPT AT SOLUTION:

I have calculated that

m1v1+m2v2=m1v1'+m2v2'

m1(0)+336kg(1.81m/s)=m1v1'+336kg(0.807m/s)

m1v1'=336kg(1.81-0.807)

m1v1'=337 kg*m/s

I'm stuck here. I tried calculating the amount of energy the second

cart should have

1/2m2(v2-v2')^2=

0.5(336)(1.81-0.807)^2=169J

and then that

169J=0.5m1(v1)^2 so that

m1=169*2/v1^2

and subbing that into

m1v1'=337 kg*m/s

(169*2/v1'^2)*v1'=337 kg*m/s

338/v1'=337

thus v1' =338/337

This however does not answer #7 and when working backwards to find the

mass it also provides the wrong answer.

Thank you for any assistance you can provide.

Sincerely,

Potato21

EDIT: Oops, dumb mistake, I got it!

**Physics Forums - The Fusion of Science and Community**

# Elastic Cart Collision of a stationary and a moving cart

Have something to add?

- Similar discussions for: Elastic Cart Collision of a stationary and a moving cart

Loading...

**Physics Forums - The Fusion of Science and Community**