Elastic potential energy and natural length of a spring- relation?

AI Thread Summary
The spring constant is inversely proportional to the natural length of a spring, indicating that longer springs have lower spring constants. There is a notable change in extension as springs approach their breaking point. At the point of failure, both strain and force remain consistent across different springs. Understanding these relationships is crucial for analyzing spring behavior under stress. This highlights the importance of strain and force in the study of elastic potential energy.
Stormzy67
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Homework Statement
The question states, a spring of length 0.5m is can be extended by 0.05m before fracturing, storing elastic energy ‘U’. Now, another spring of the same material but of half the length(0.25) is also stretched to its maximum extension.
What will be the new elastic energy in terms of ‘U’?
Relevant Equations
F=kx , E=1/2 kx^2, Young’s modulus?
I figured out that the spring constant is inversely proportional to the natural length, but there’s still an unknown change in a quantity( most likely extension).
 
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Is there something that’s the same for both springs at the point where they break?
 
The strain?
 
Stormzy67 said:
The strain?
Yes. Also, the force.
 

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