- #1

tahayassen

- 270

- 1

To calculate p

_{4}in example 1.7, voltage of 8V is multiplied by a current of -0.2I. Firstly, why is the current negative? Secondly, why do they substitute a value of 5A for I. Where did they get this value?

I tried to do practice problem 1.7, but I don't seem to get the right answer for p

_{3}when I use a voltage of 3V and a current of 0.6(3)A.