Electric Feld Intensity Question

AI Thread Summary
The discussion focuses on calculating the electric field intensity vector at point P (5,6) due to an infinite line charge described by the equation 2x + 3y = 7 with a linear charge density of 3 µC/m. The user seeks clarification on whether to use the distances from the x-intercept and y-intercept as R and R' in the electric field equation. It is suggested to connect point P to the line orthogonally and denote this distance as r0, with the electric field direction being in the positive x and y directions. The magnitude of the electric field can be determined by integrating k*dq/r^2, where r is expressed in terms of r0 and the angle theta. The discussion emphasizes the importance of symmetry and proper integration limits in solving the problem.
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Homework Statement


An electric charge is distributed along an infinite line (2x+3y=7) in xy-plane with density pl = 3uC/m. Find the Efield intensity vector at point P (5,6).

Homework Equations


E = Integral of pl/ (4*pi*E) * (R - R')/ (R-R')^3


The Attempt at a Solution


I just wanted to double check if all i need to do is find the distance of point P from the y-int and x-int and then just use them as R and R' in the above equation
 
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?? Did you mean x-intercept & y-intercept? If so, i think the answer is no.

Anyway - connect P(5,6) to the line at the point where they meet orthogonally. Call this distance r0.

By symmetry, the direction of E is obviously in the direction of this normal in the +x, +y direction.

The magnitude you can get by integrating k*dq/r^2 where r = r0sec(theta), k = 9e9 in SI units and theta is the angle between r0 and an element of charge along the line dq = pl*r*d(theta). Integrate from 0 to pi/2 & double the result.
 
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