Electric field between two spheres

AI Thread Summary
The electric field between two spheres, where the inner sphere has charge +Q and the outer sphere has charge -Q/2, can be determined using Gauss' law. The electric field E in the region between the spheres (a < r < b) is given by E = Q/(ε*4*pi*r^2). The outer sphere does not affect the electric field at the inner sphere due to the cancellation of fields from charges outside the radius r, similar to gravitational effects inside a spherical shell. The problem does not specify whether the spheres are conducting or insulating, but this distinction is irrelevant for calculating the electric field in this scenario. Understanding the application of Gauss' law is crucial for solving such problems effectively.
DrummingAtom
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Homework Statement



If the inner sphere of radius a has charge +Q and the outer sphere of radius b has charge -Q/2. What's the electric field between them?

The Attempt at a Solution



If I use Gauss' law then I would have E*4*pi*a^2 = Q/ε then just solve for E. Is that correct? It seems like the outer sphere would affect the E-field on the inner sphere. By the way, they don't say that these are conducting spheres.

Thanks for any help.
 
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DrummingAtom said:

Homework Statement



If the inner sphere of radius a has charge +Q and the outer sphere of radius b has charge -Q/2. What's the electric field between them?

The Attempt at a Solution



If I use Gauss' law then I would have E*4*pi*a^2 = Q/ε then just solve for E. Is that correct? It seems like the outer sphere would affect the E-field on the inner sphere. By the way, they don't say that these are conducting spheres.

Thanks for any help.

You have the field at r = a correct, but what about a < r < b? No, the outer sphere does no affect the E field on the inner sphere. Believe in Dr. Gauss! And also no, it doesn't matter if the sphers are conducting or insulators in this case.
 
Thanks for the reply. Is this the E-field between the two spheres:

E = Q/(ε*4*pi*r^2) for a < r < b ?

I'm still confused how the outer sphere doesn't affect the E-field between them..
 
DrummingAtom said:
Thanks for the reply. Is this the E-field between the two spheres:

E = Q/(ε*4*pi*r^2) for a < r < b ?
Right.

I'm still confused how the outer sphere doesn't affect the E-field between them..

For the same reason that, if you go inside the Earth, the only part exerting gravity on you is the part below you.

At a point r in your sphere, some of the charges outside r will set up a + field and others will set up a - field. Some will push a test charge at r one way, others the opposite way. The net result is complete cancellation of each others' fields. It's not an easy task to do that integration, so again - believe Dr. Gauss!
 
DrummingAtom said:

Homework Statement



If the inner sphere of radius a has charge +Q and the outer sphere of radius b has charge -Q/2. What's the electric field between them?
There are several additional pieces of information needed before this problem could possibly be solved.

Questions:
Are the spheres concentric? (Do they have a common center?)

Is the outer sphere actually a spherical shell? -- That's was is implied, seemingly.

Is the charge distributed uniformly? -- or at least in some sort of symmetrical manner

The Attempt at a Solution



If I use Gauss' law then I would have E*4*pi*a^2 = Q/ε then just solve for E. Is that correct? It seems like the outer sphere would affect the E-field on the inner sphere. By the way, they don't say that these are conducting spheres.

Thanks for any help.
Suppose you have a uniformly charged spherical shell. What is the electric field inside the shell?
This situation is often covered even before introducing Gauss's Law.​
 
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