Electric Field Calculations for Stationary Charges and a Dipole at Point P(0,4m)

AI Thread Summary
The discussion focuses on calculating the electric field vector at point P(0,4m) due to two stationary charges, q1 and q2, and determining the torque on a dipole located at the same point. The user has computed the electric fields E1 and E2 but is uncertain about the sign of E1, suspecting it to be negative due to its downward direction. Clarification is provided that while electric fields are vector quantities, their components can be positive or negative based on direction. Additionally, there is confusion regarding the correct use of arctan to find the angle for E2, with advice given to ensure the dimensions of the triangle used for calculations are accurate. Accurate significant figures and units in calculations are also emphasized.
BHH
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Homework Statement


The picture below shows two stationary charges q1= +2mC and q2= -15 mC.
and I need to find the electric field vector at field point P(0,4m). E= [px, py] .

Also
A little dipole is positions in P(0,4m) and is given with p= [px,py]=[2*10^-8 ,0] Cm.

Find the torque that acts on the dipole because of the electric field and its potential energy

Homework Equations


E=k*q/r^2

The Attempt at a Solution


I have found out that E1=4.5*10[6][/SUP] and E2= 1.7*10^6. I am not sure if the electric field E1 is negative or positive ? I think its negative because the vector goes downwards. And when I find the angle for E2 do I use arctan(8/2)?
 

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BHH said:
I have found out that E1=4.5*10[6][/SUP] and E2= 1.7*10^6.
OK. But I would keep an extra significant figure while doing the calculations. Then round off to the appropriate number of significant figures at the end. Also, don't forget the units.
I am not sure if the electric field E1 is negative or positive ? I think its negative because the vector goes downwards.
Electric field is a vector quantity. It is not good language to say that a vector is negative. However, the components of a vector can be negative or positive. So, if the field points downward (along the negative y axis) then you would say that the y component of the electric field is negative.

And when I find the angle for E2 do I use arctan(8/2)?
This does not look right. Are you trying to find the angle that E2 makes to the horizontal direction or the vertical direction? If you are constructing a right triangle to help find the angle, make sure you have the dimensions of the sides of the triangle correct.
 
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