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sazmat
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Suppose everywhere in space charge is distributed with uniform and constant volume charge density. What will be Electric field at any point in space??
1>..Symmetry demands it to be zero,
2>..if I consider the space to be a sphere of infinite radius with constant charge density on its volume then using the formula of field inside a uniformly charged sphere of finite radius I get E=(p*r)/(3*Eo)
where p=charge density
r= distance from center of sphere
Eo=8.82*10^-12 (permittivity of free space)
3>..if I consider the space to be a cylinder of infinite radius and infinite length with constant charge density on its volume then using the formula of field inside a uniformly charged cylinder of finite radius and infinite length I get E=(p*r)/(2*Eo)
where p=charge density
r= distance from the axis of cylinder
Eo=8.82*10^-12 (permittivity of free space)
Different approaches give different answers. Why is that so? and Whats the correct answer?
1>..Symmetry demands it to be zero,
2>..if I consider the space to be a sphere of infinite radius with constant charge density on its volume then using the formula of field inside a uniformly charged sphere of finite radius I get E=(p*r)/(3*Eo)
where p=charge density
r= distance from center of sphere
Eo=8.82*10^-12 (permittivity of free space)
3>..if I consider the space to be a cylinder of infinite radius and infinite length with constant charge density on its volume then using the formula of field inside a uniformly charged cylinder of finite radius and infinite length I get E=(p*r)/(2*Eo)
where p=charge density
r= distance from the axis of cylinder
Eo=8.82*10^-12 (permittivity of free space)
Different approaches give different answers. Why is that so? and Whats the correct answer?