- #1
gracy
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Homework Statement
The electric potential on the surface of a sphere of radius R and charge ##3##×##10^-6## is 500V.The intensity of electric field on the surface of the sphere (in N/C)is
Homework Equations
##V##=##(\frac{1}{4πε0}\frac{q}{R})^2##
The Attempt at a Solution
Actually I have solution but still I am unable to understand.So ,instead of my attempt at a solution .I 'll post solution itself.
##V##=##(\frac{1}{4πε0}\frac{q}{R})^2##
##E##=##\frac{\left(\frac{1}{4πε0}\frac{q}{R}\right)^2}{\frac{q}{4πε0}}##
=##\frac{25×10^4}{27×10^3}##
=##\frac{250}{27}##
I want to how the above formula of E is derived.