Electric field in an arbitrary number of dimensions

AI Thread Summary
The discussion focuses on using Gauss's law to determine the electric field in 1+1 dimensional spacetime, specifically addressing the challenge of quantifying the infinitesimal area at the two endpoints of a Gaussian surface surrounding a point charge. Participants explore the implications of different dimensions on the electric field and the necessary adjustments to the units of ε₀ in the equation. The conversation shifts to the magnetic field in arbitrary dimensions, noting that while the divergence of the magnetic field generalizes, its generation remains tied to changing electric fields as described by Faraday's Law. The complexity of generalizing magnetic fields to more than three dimensions is acknowledged, with a discussion on the components of electric and magnetic fields in higher-dimensional spacetimes. The exchange highlights the intricate relationship between electric and magnetic fields across varying dimensions.
spaghetti3451
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I am looking to use Gauss's law to find the electric field in ##1+1## dimensional spacetime:

##\int \vec{E}\cdot d\vec{A}=\frac{Q}{\epsilon_{0}}##

Now, for a point charge in ##1+1## dimensional spacetime, the Gaussian surface is the two endpoints (a distance ##r## away from the point charge) along which the electric field points outwards. How do I account for ##d\vec{A}## of the two endpoints?
 
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The integral gets a sum over the two endpoints.
 
I know that, but I am finding it difficult to form a quantitative value for the infinitesimal area of the two points.
 
Just add the two electric field strengths? Your field will have different dimensions anyway, so it fits.
 
I don't exactly understand what you mean when you say that the field will have different dimensions.
 
Sorry, I didn't mean the field itself, I meant the equation. To work, ##\epsilon_0## needs different units, which means the whole equation has different units.
 
Thanks!
 
The more interesting question is the magnetic field in an arbitrary number of dimensions...
 
Well, ##\nabla\cdot{\vec{B}}=0## generalises to ##\partial_{\mu}B^{\mu}=0##, I suppose, which means that ##B## has inverse dimensions of the length in any spacetime.

Am I right?
 
  • #10
But how is it generated? ;)
 
  • #11
It's generated by a changing electric field, which comes from Faraday's Law.

##\epsilon_{ijk}\partial_{i}E_{i}=-\partial_{t}B_{i}## is Faraday's law in 3 dimensions.

I guess the epsilon symbol ought to have more (or less) spatial indices as the number of spatial dimensions increases (or decreases)?
 
  • #12
There is no obvious generalization of this law to N dimensions.
 
  • #13
Is this why the magnetic field cannot be generalised to more than 3 dimensions?
 
  • #14
Crudely...

The electric field is "time-space part" of the [antisymmetric] field tensor, orthogonal to the observer's 4-velocity. In (n+1)-spacetime, it has n independent components. In 4+1, Ex, Ey, Ez, Ew.

The magnetic field is the remaining part... also orthogonal to the observer's 4-velocity. In (n+1)-spacetime, it has n(n-1)/2 independent components... Counting the number of strictly lower triangular space-space components. In 4+1, Bxy, Byz, Bzx, Bxw, Byw, Bzw (up to signs). The epsilon symbol or its equivalent will appear.

For n=3, the electric and magnetic field each have 3 components.
 

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