1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Electric Field of Dipole, straight line, ring, disk, shell, and sold sphere

  1. Jul 9, 2008 #1
    1. The problem statement, all variables and given/known data
    Okay, I totally do not understand how to derive the electric field made by a dipole or a line or a ring or etc.



    2. Relevant equations
    When finding the electric field, when you make an estimate, saying that the test charge is very far away, it should be similar to kQ/r^2

    You may need to know lambda, the linear charge distribution and the ones for area and volume.


    3. The attempt at a solution
    I've made lots of attempts. Its 2 am right now, but I will upload it tomorrow if anyone needs it. Someone asked a question like this before, if that helps, but I didn't understand the answer and I need help with all of these things.
     
  2. jcsd
  3. Jul 9, 2008 #2

    Defennder

    User Avatar
    Homework Helper

    You have to be more specific if we are to help. But in general, you should make use of this:

    [tex]dE = \frac{dq}{4\pi \varepsilon r(x,y,z)^2}[/tex]. But you probably already knew that. r(x,y,z) is just the distance from the point at which you want you find the E-field to the differential charged element dq in terms of x,y,z coordinates. dq is either lambda dL, rho dV where lambda and rho are the charge densities of the charged object.

    And I don't think you need to make any assumption about the test charge being very far away. There are a number of such problems in this forum recently. Do a search of this and you'll find some of them.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Electric Field of Dipole, straight line, ring, disk, shell, and sold sphere
Loading...