Electric Field Problem: Motion of Charges Near Two Fixed Points

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The discussion centers on the motion of a third charge near two fixed point charges of equal magnitude. It confirms that a negative charge at point a will accelerate toward the lower-right, a positive charge at point b will accelerate up, and a negative charge at point e will also accelerate up. However, there is uncertainty regarding the initial motion of a negative charge at point a, as it may accelerate downward instead. The importance of visualizing electric field lines is emphasized to understand the direction of force on different charges. Overall, the correct behaviors of charges in the electric field are highlighted.
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Consider the arrangement of two fixed point charges, equal in magnitude, shown in the figure. Which of the following statements are correct for the initial motion of a third charge if it is released from rest in the vicinity of the two charges shown?

True or False:

A negative charge at point a will accelerate toward the lower-right.
A positive charge at point b will accelerate up.
A negative charge at point e will accelerate up.
A positive charge at point c will accelerate toward the lower-left.
A positive charge at point d will accelerate up.
 

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it might help if you draw electric field lines running from the positive to negative charge to help yourself visualize what is going on.
if you don't know what electric field lines are there is a perfect example of how to draw electric field lines between a positive and negative charge

http://en.wikipedia.org/wiki/File:VFPt_charges_plus_minus_thumb.svg

a positive charge will move in the direction of the arrows, and a negative in the opposite direction.
 
A negative charge at point a will accelerate toward the lower-right.
A positive charge at point b will accelerate up.
A negative charge at point e will accelerate up.....these are correct
 
brucemaster said:
A negative charge at point a will accelerate toward the lower-right.
A positive charge at point b will accelerate up.
A negative charge at point e will accelerate up.....these are correct

Not sure about the first one. The electric field line would point straight up at that point. A negative charge would be accelerated straight down. Then it would of course move to the right as well, but the problem asked for the initial motion.
 
I'm working through something and want to make sure I understand the physics. In a system with three wave components at 120° phase separation, the total energy calculation depends on how we treat them: If coherent (add amplitudes first, then square): E = (A₁ + A₂ + A₃)² = 0 If independent (square each, then add): E = A₁² + A₂² + A₃² = 3/2 = constant In three-phase electrical systems, we treat the phases as independent — total power is sum of individual powers. In light interference...

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