Electric field strength of a wire comparison

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SUMMARY

The discussion centers on calculating the electric field strength at a distance from a charged wire, specifically comparing values at 7.79 cm and 12.7 cm. The initial electric field strength is given as 2660 N/C at 7.79 cm. The incorrect approach involved using the formula E = (9*10^9) Q/r^2, which is not applicable for this scenario. Instead, Gauss's Law should be utilized to determine the electric field strength, leading to the correct calculation for the distance of 12.7 cm.

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  • Understanding of electric field concepts
  • Familiarity with Gauss's Law
  • Knowledge of the relationship between charge, distance, and electric field strength
  • Basic algebra for manipulating equations
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  • Learn how to derive electric field strength from charge distributions
  • Explore the concept of electric field lines and their significance
  • Practice problems involving electric fields around charged objects
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1. Homework Statement

The electric field strength 7.79 cm from a very long charged wire is 2660 N/C. What is the electric field strength (in N/C) 12.7 cm from the wire?

2. Homework Equations

E= (9*10^9) Q/ r^2

3. The Attempt at a Solution

i have energy. so is tried to solve backwards for the first one for Q. Then i plugged in the new Q with relation to 0.127 m. I got 1001 N/C which is wrong. Am I even using the right formula?
 
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Do you know Gauss's Law?
 
ya is that what i needed to use?
 

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