Electric field strength of a wire comparison

AI Thread Summary
The discussion focuses on calculating the electric field strength at a distance from a charged wire, with an initial value of 2660 N/C at 7.79 cm. The user attempts to find the electric field strength at 12.7 cm using the formula E = (9*10^9) Q/ r^2 but ends up with an incorrect result of 1001 N/C. There is uncertainty about whether the correct formula is being used, with a suggestion to consider Gauss's Law for the calculation. The conversation highlights the importance of using the appropriate equations for electric fields around charged conductors. Understanding the correct application of Gauss's Law is crucial for solving such problems accurately.
pickleparty
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1. Homework Statement

The electric field strength 7.79 cm from a very long charged wire is 2660 N/C. What is the electric field strength (in N/C) 12.7 cm from the wire?

2. Homework Equations

E= (9*10^9) Q/ r^2

3. The Attempt at a Solution

i have energy. so is tried to solve backwards for the first one for Q. Then i plugged in the new Q with relation to 0.127 m. I got 1001 N/C which is wrong. Am I even using the right formula?
 
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Do you know Gauss's Law?
 
ya is that what i needed to use?
 
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Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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