Electric fields and mean free path?

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SUMMARY

The discussion centers on calculating the required electric field strength to achieve a collision energy of 5 eV for a particle with a mean free path of 50 nm. The initial calculation of 100 MV/m was incorrect due to unit mismanagement. Proper unit conversion is crucial for accurate electric field strength determination in particle acceleration scenarios.

PREREQUISITES
  • Understanding of electric fields and their units (MV/m)
  • Knowledge of particle acceleration principles
  • Familiarity with mean free path concepts in physics
  • Basic skills in unit conversion and dimensional analysis
NEXT STEPS
  • Review the principles of electric field strength calculations in particle physics
  • Study the concept of mean free path and its implications in collision theory
  • Learn about energy conversion between electron volts (eV) and joules (J)
  • Explore advanced particle acceleration techniques and their applications
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Physics students, researchers in particle physics, and engineers working on particle acceleration systems will benefit from this discussion.

hobbs125
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Just need someone to tell me if I'm doing this right.

If I have accelerated a particle in which the mean free path is 50nm and I need the collision to be 5eV would this be correct in determining the required electric field strength?

5/.00000005 = 100MV/m
 
Last edited:
Physics news on Phys.org
No. Double check your units.
 

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