Electric Fields involving Disks

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SUMMARY

The discussion centers on the electric field generated by a charged circular glass disk with a diameter of 6 meters, which exerts a force of 8e-15 N on a nearby chloride ion located 0.5 mm from the disk. The participants confirm that the charged disk is the source of the electric field affecting the chloride ion, while clarifying that the force on the ion is not equal to the electric field itself. The correct charge of the disk was calculated to be approximately -0.000025 C, but the sign was later identified as incorrect, indicating the disk is positively charged due to the attraction of the negatively charged chloride ion.

PREREQUISITES
  • Understanding of electric fields and forces, specifically F=qE.
  • Knowledge of the properties of charged particles, including ions.
  • Familiarity with the concept of electric field due to a disk.
  • Basic skills in algebra for solving equations involving electric forces.
NEXT STEPS
  • Study the derivation of the electric field of a charged disk.
  • Learn about the significance of charge signs in electric force calculations.
  • Explore the concept of electric field lines and their representation.
  • Investigate the role of significant figures in scientific calculations.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding electrostatics, particularly the behavior of charged objects and electric fields.

demonhunter19
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Homework Statement


A thin circular sheet of glass of diameter 6 meters is rubbed with a cloth on one surface, and becomes charged uniformly. A chloride ion (a chlorine atom which has gained one extra electron) passes near the glass sheet. When the chloride ion is near the center of the sheet, at a location 0.5 mm from the sheet, it experiences an electric force of 8e-15 N, toward the glass sheet.
It will be useful to you to draw a diagram on paper, showing field vectors, force vectors, and charges, before answering the following questions about this situation.

Which of the following statements about this situation are correct? Select all that apply.

  • The charged disk is the source of the electric field that causes the force on the chloride ion.

    The force on the chloride ion is equal to the electric field of the glass sheet.

    The electric field that acts on the chloride ion is due to the charge on the glass sheet and to the charge on the chloride ion.

    The electric field of the glass sheet is equal to the electric field of the chloride ion.
    The net electric field at the location of the chloride ion is zero.

Homework Equations


Electric Field of a Disk:
e15-8.jpg

Electric FORCE due to some charge: F=qE

The Attempt at a Solution


I'm not sure which statement is correct, but it seems like the first three (The charged disk is the source of the electric field that causes the force on the chloride ion. The force on the chloride ion is equal to the electric field of the glass sheet. The electric field that acts on the chloride ion is due to the charge on the glass sheet and to the charge on the chloride ion) are correct.

I know the electric force exerted on the Chlorine atom, which is 8e-15N, and I set it equal to (-1.6e-19)(Q/(6^2*pi))/2*ε), which is really the relative equation between the electric force and the electric field, F=qE, q being the charge.

The answer I got for Q (the charge of the disk, which is what the 2nd part of the question is asking) is -.000025C. I'm not sure if it's right, but given the relative size of the disk, it makes sense.

And I'm still not certain about which statements above are correct (1st part of question)
 
Last edited:
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Welcome to PF demonhunter19,

demonhunter19 said:
I'm not sure which statement is correct, but it seems like the first three (The charged disk is the source of the electric field that causes the force on the chloride ion. The force on the chloride ion is equal to the electric field of the glass sheet. The electric field that acts on the chloride ion is due to the charge on the glass sheet and to the charge on the chloride ion) are correct.

I know the electric force exerted on the Chlorine atom, which is 8e-15N, and I set it equal to (-1.6e-19)(Q/(6^2*pi))/2*ε), which is really the relative equation between the electric force and the electric field, F=qE, q being the charge.

The answer I got for Q (the charge of the disk, which is what the 2nd part of the question is asking) is -.000025C. I'm not sure if it's right, but given the relative size of the disk, it makes sense.

And I'm still not certain about which statements above are correct (1st part of question)
Let's take a look at the first three statements then:
demonhunter19 said:
The charged disk is the source of the electric field that causes the force on the chloride ion.
I agree :approve:
demonhunter19 said:
The force on the chloride ion is equal to the electric field of the glass sheet.
What are the units of force? What are the units of the electric field?
demonhunter19 said:
The electric field that acts on the chloride ion is due to the charge on the glass sheet and to the charge on the chloride ion.
Suppose we have a completely empty region of space, devoid of any matter, energy or fields. Suppose then we place a single point charge in this region. Would this create an electric field in the region?
 
Hootenanny said:
Welcome to PF demonhunter19,Let's take a look at the first three statements then:

I agree :approve:

What are the units of force? What are the units of the electric field?

Suppose we have a completely empty region of space, devoid of any matter, energy or fields. Suppose then we place a single point charge in this region. Would this create an electric field in the region?
Right, the 2nd statement cannot be true, since Force is in Newtons, whilst the electric field is in Newtons/Coulombs. As for the 3rd statement, I'm not entirely sure, but I would imagine that at any time or space, there will always be an electric field created by a charge.
 
demonhunter19 said:
Right, the 2nd statement cannot be true, since Force is in Newtons, whilst the electric field is in Newtons/Coulombs.
Correct :approve:
demonhunter19 said:
As for the 3rd statement, I'm not entirely sure, but I would imagine that at any time or space, there will always be an electric field created by a charge.
Again correct, does this electric field act on the point charge itself?
 
Hootenanny said:
Correct :approve:

Again correct, does this electric field act on the point charge itself?
I don't think so. It would also act on other objects (assuming that there are other objects within that electric field).
 
demonhunter19 said:
I don't think so. It would also act on other objects (assuming that there are other objects within that electric field).
Correct :approve:. So how can the field that acts on the chloride ion be due to the chloride ion?
 
Hootenanny said:
Correct :approve:. So how can the field that acts on the chloride ion be due to the chloride ion?
Ah, now I see the mistake! Thanks. So the only statement that is correct out of the 5 is the first one.
 
demonhunter19 said:
Ah, now I see the mistake! Thanks. So the only statement that is correct out of the 5 is the first one.
No problem, sounds about right to me.
 
Now I'm just stuck on finding the charge of the glass disk.

We are given the amount of electric force acting on the chlorine ion, which has a charge of -1.6e-19.

And with the equation that relates electric force and electric field, F=qE, I can just set the equations up like this:

8e-15=(-1.6e-19)(Q/(3^2*pi))/(2*8.85e-12) and solve for Q, right? Then again, that's an approximation, and I'm not entirely sure if what I did right there is correct (since webassign is telling me that that is the wrong answer [-.000025]). Could it be the sign?

edit: Wait, it might be the sign, I just realized the chlorine ion has a negative charge, and the electric force is TOWARDS the glass disk. Which would also mean that the disk is positive? Need some help for this ;[
 
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  • #10
demonhunter19 said:
Now I'm just stuck on finding the charge of the glass disk.

We are given the amount of electric force acting on the chlorine ion, which has a charge of -1.6e-19.

And with the equation that relates electric force and electric field, F=qE, I can just set the equations up like this:

8e-15=(-1.6e-19)(Q/(3^2*pi))/(2*8.85e-12) and solve for Q, right? Then again, that's an approximation, and I'm not entirely sure if what I did right there is correct (since webassign is telling me that that is the wrong answer [-.000025]). Could it be the sign?

edit: Wait, it might be the sign, I just realized the chlorine ion has a negative charge, and the electric force is TOWARDS the glass disk. Which would also mean that the disk is positive? Need some help for this ;[
Your solution looks fine to me, except for the sign. As you correctly point out in your edit, the disk is positively charged. You also might want to check if there is a required number of significant figures, WebAssign is notoriously fickle about significant figures.
 
  • #11
Yep, thank you for your help, Hootenanny!
 

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