Understanding Inward Flux of an Object

  • Thread starter Thread starter Ronnin
  • Start date Start date
  • Tags Tags
    Flux
AI Thread Summary
The discussion centers on how the material type, whether a conductor or insulator, influences the inward flux of an object containing a charge. It is clarified that conductors allow for higher flux due to their ability to conduct electricity, while insulators like the specified block will exhibit lower flux. The user expresses confusion about calculating flux for a non-uniform shape, questioning the validity of a provided solution. It is suggested that posting the entire homework question could yield more precise assistance. Understanding the relationship between material properties and electric flux is crucial for accurate problem-solving in this context.
Ronnin
Messages
168
Reaction score
1
I'm a bit confused on an issue, does whether an object is a conductor or insulator affect the inward flux in any way if the object contains a charge? The reason I ask is on one of my homework questions it states that a insulating block of dimentions 3x2x1m contains a charge of -24nC. Then it asks to find the flux on one side that is 6m. The solution shows basically q/Enot/6, but how can this be? Because of the shape of the block, flux is not going to be uniform for each side. Is my thinking correct, or should I just post the entire question.
 
Physics news on Phys.org
Yes, the type of material (conductor or insulator) can affect the inward flux. Conductors are better at conducting electricity, so they will have higher flux than insulators. In your example, since the block is insulating, the inward flux will be lower than if it were a conductor. To answer your question, you should post the entire homework question so we can provide a more specific answer.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top